Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:22Z
∑_{k=1}^{n} k = n(n+1)/2
det| 11 4 ; 5 12 | = 112
75K
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
det| 11 9 ; 0 12 | = 132
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}