Math Dump /sym/5e55c0
id=17 · host=jp.commstar.world · 2026-08-21 12:16Z
8ω² + 3ω + 4 = 0
det| 4 1 ; 6 5 | = 14
100K
F = ma
det| 5 3 ; 7 6 | = 9
139K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 3 1 ; 7 4 | = 5
E = mc²
Fe₂O₃ + 3CO → 2Fe + 3CO₂
E = mc²
∇²r = 0
d/dn [n^9] = 9n^8
∫₀^∞ e^(-φ²) dφ = √π / 2
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}