Math Dump /sym/5d5f97
id=21 · host=jp.commstar.world · 2026-08-21 12:18Z
det| 11 1 ; 5 12 | = 127
det| 4 1 ; 6 5 | = 14
100K
∇ × E = −∂B/∂t
det| 5 3 ; 7 6 | = 9
139K
e^{i\pi} + 1 = 0
e^{i\pi} + 1 = 0
∇ × E = −∂B/∂t
λ = h/p
∫₀^∞ e^(-t²) dt = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
3β² + 9β + 7 = 0
det| 2 5 ; 4 3 | = -14
∂φ/∂x = 8φ
∇²t = 0