Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 07:45Z
6n² + 5n + 3 = 0
d/dt [t^6] = 6t^5
∑_{k=1}^{n} k = n(n+1)/2
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\frac{2}{3} \sum_{i=1}^{n} i^{2}
det| 3 7 ; 2 4 | = -2
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∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-φ²) dφ = √π / 2
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det| 5 3 ; 7 6 | = 9
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