Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:02Z
d/dα [α^11] = 11α^10
\frac{3}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
233K
λ = h/p
det| 9 4 ; 1 10 | = 86
100K
10r² + 3r + 0 = 0
det| 5 3 ; 2 6 | = 24
375K
det| 4 4 ; 5 5 | = 0
139K
e^{i\pi} + 1 = 0
det| 4 1 ; 1 5 | = 19