Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:20Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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8β² + 2β + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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det| 3 6 ; 0 4 | = 12
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CH₄ + 2O₂ → CO₂ + 2H₂O
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