Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:39Z
E = mc²
det| 10 7 ; 4 11 | = 82
det| 10 4 ; 1 11 | = 106
63K
λ = h/p
det| 5 6 ; 7 6 | = -12
366K
4θ² + 9θ + 6 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
319K
det| 8 5 ; 5 9 | = 47
∑_{k=1}^{n} k = n(n+1)/2
359K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O