Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:44Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
F = ma
det| 5 6 ; 7 6 | = -12
191K
∫₀^∞ e^(-φ²) dφ = √π / 2
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 9 4 ; 1 10 | = 86
153K
1x² + 5x + 7 = 0
∫₀^∞ e^(-t²) dt = √π / 2
473K
∇²ψ = 0