Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:30Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 7 9 ; 1 8 | = 47
479K
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
276K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
153K
det| 3 7 ; 2 4 | = -2
473K