Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:31Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
det| 6 6 ; 3 7 | = 24
198K
E = mc²
e^{i\pi} + 1 = 0
det| 4 6 ; 4 5 | = -4
366K
det| 9 4 ; 1 10 | = 86
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
176K
∑_{k=1}^{n} k = n(n+1)/2
319K