Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:43Z
11t² + 7t + 4 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 6 ; 1 8 | = 50
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CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
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det| 1 4 ; 3 2 | = -10
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∫₀^∞ e^(-ψ²) dψ = √π / 2
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CH₄ + 2O₂ → CO₂ + 2H₂O
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