Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:38Z
∂r/∂φ = 2r
\binom{n}{k} = \frac{n!}{k!(n-k)!}
326K
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-φ²) dφ = √π / 2
201K
\oint_C \vec{F}\cdot d\vec{r} = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
λ = h/p
∫₀^∞ e^(-φ²) dφ = √π / 2
233K
N₂ + 3H₂ ⇌ 2NH₃
e^{i\pi} + 1 = 0
9t² + 1t + 0 = 0