Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:39Z
det| 3 3 ; 5 4 | = -3
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∇²β = 0
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
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AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 3 7 ; 2 4 | = -2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 10 9 ; 0 11 | = 110
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