Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-21 20:08Z
det| 10 8 ; 0 11 | = 110
∑_{k=1}^{n} k = n(n+1)/2
352K
det| 5 2 ; 3 6 | = 24
192K
∇²y = 0
∑_{k=1}^{n} k = n(n+1)/2
143K
12φ² + 8φ + 1 = 0
N₂ + 3H₂ ⇌ 2NH₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
176K
d/dy [y^11] = 11y^10
296K
det| 7 4 ; 4 8 | = 40
404K