Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:43Z
E = mc²
det| 11 5 ; 0 12 | = 132
326K
det| 7 4 ; 4 8 | = 40
198K
det| 10 7 ; 4 11 | = 82
∑_{k=1}^{n} k = n(n+1)/2
155K
λ = h/p
∫₀^∞ e^(-t²) dt = √π / 2
201K
4θ² + 9θ + 6 = 0
det| 4 6 ; 4 5 | = -4
176K
det| 10 7 ; 3 11 | = 89
319K
det| 8 5 ; 5 9 | = 47
\frac{1}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dx [x^12] = 12x^11