Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:21Z
det| 3 3 ; 5 4 | = -3
det| 4 6 ; 4 5 | = -4
75K
∇²β = 0
∫₀^∞ e^(-x²) dx = √π / 2
276K
∫₀^∞ e^(-t²) dt = √π / 2
129K
e^{i\pi} + 1 = 0
E = mc²
det| 11 9 ; 5 12 | = 87
153K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
E = mc²
det| 3 7 ; 2 4 | = -2
det| 8 5 ; 1 9 | = 67
∂t/∂β = 2t