Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:38Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
75K
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 12 1 ; 4 13 | = 152
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 5 9 ; 7 6 | = -33
1K
det| 5 6 ; 7 6 | = -12
153K
det| 12 1 ; 1 13 | = 155
\lim_{t\to 0} \frac{\sin t}{t} = 1
N₂ + 3H₂ ⇌ 2NH₃