Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:11Z
det| 3 3 ; 5 4 | = -3
det| 7 2 ; 7 8 | = 42
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∑_{k=1}^{n} k = n(n+1)/2
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∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
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e^{i\pi} + 1 = 0
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 3 7 ; 2 4 | = -2
det| 9 4 ; 1 10 | = 86
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