Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-21 08:15Z
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∫₀^∞ e^(-z²) dz = √π / 2
192K
2H₂ + O₂ → 2H₂O
det| 7 4 ; 4 8 | = 40
143K
7ψ² + 9ψ + 6 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
176K
\oint_C \vec{F}\cdot d\vec{r} = 0
296K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
404K