Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:42Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12β² + 9β + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
∂z/∂n = 8z
det| 4 8 ; 3 5 | = -4
390K
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
473K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-ψ²) dψ = √π / 2
4γ² + 9γ + 7 = 0
1r² + 3r + 3 = 0