Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:08Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
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6φ² + 8φ + 4 = 0
∂φ/∂φ = 1φ
∑_{k=1}^{n} k = n(n+1)/2
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det| 4 8 ; 1 5 | = 12
det| 9 4 ; 1 10 | = 86
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det| 5 6 ; 2 6 | = 18
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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