Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:56Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 6 ; 1 8 | = 50
479K
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
276K
∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
det| 3 7 ; 2 4 | = -2
191K
∫₀^∞ e^(-t²) dt = √π / 2
1K
∫₀^∞ e^(-t²) dt = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
188K