Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:24Z
11t² + 7t + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
198K
E = mc²
det| 5 6 ; 7 6 | = -12
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{2}{2} \sum_{i=1}^{n} i^{2}
366K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
176K
det| 9 4 ; 1 10 | = 86
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 10 1 ; 4 11 | = 106
∑_{k=1}^{n} k = n(n+1)/2