Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:19Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
276K
F = ma
det| 12 1 ; 4 13 | = 152
1K
∑_{k=1}^{n} k = n(n+1)/2
153K
det| 11 9 ; 5 12 | = 87
473K