Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 01:38Z
\frac{12}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
326K
\lim_{t\to 0} \frac{\sin t}{t} = 1
198K
∫₀^∞ e^(-r²) dr = √π / 2
det| 10 9 ; 0 11 | = 110
63K
det| 5 3 ; 6 6 | = 12
∑_{k=1}^{n} k = n(n+1)/2
366K
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
263K
9x² + 6x + 1 = 0
det| 3 1 ; 4 4 | = 8