Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:59Z
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
326K
det| 10 7 ; 4 11 | = 82
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
155K
\frac{12}{6} \sum_{i=1}^{n} i^{2}
63K
λ = h/p
4θ² + 9θ + 6 = 0
det| 8 5 ; 5 9 | = 47
\oint_C \vec{F}\cdot d\vec{r} = 0
359K
∑_{k=1}^{n} k = n(n+1)/2
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dx [x^12] = 12x^11
3n² + 5n + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0