Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:28Z
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 9 4 ; 1 10 | = 86
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
10n² + 4n + 5 = 0
det| 11 9 ; 5 12 | = 87
153K
∫₀^∞ e^(-ψ²) dψ = √π / 2
473K
∑_{k=1}^{n} k = n(n+1)/2
338K