Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:40Z
d/dα [α^11] = 11α^10
∑_{k=1}^{n} k = n(n+1)/2
278K
\frac{3}{5} \sum_{i=1}^{n} i^{2}
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
330K
det| 7 4 ; 4 8 | = 40
375K
det| 10 9 ; 0 11 | = 110
139K