Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
276K
det| 1 1 ; 5 2 | = -3
129K
F = ma
det| 5 2 ; 3 6 | = 24
191K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
390K
∫₀^∞ e^(-t²) dt = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
188K