Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:22Z
11t² + 7t + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
198K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
155K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{α\to 0} \frac{\sin α}{α} = 1
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 9 4 ; 1 10 | = 86
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d/dy [y^11] = 11y^10
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