Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:14Z
11t² + 7t + 4 = 0
det| 3 6 ; 0 4 | = 12
326K
det| 3 1 ; 7 4 | = 5
198K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 11 4 ; 5 12 | = 112
366K
\lim_{t\to 0} \frac{\sin t}{t} = 1
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
359K