Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:00Z
det| 3 3 ; 5 4 | = -3
∇²β = 0
det| 11 5 ; 0 12 | = 132
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det| 7 2 ; 7 8 | = 42
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e^{i\pi} + 1 = 0
det| 1 4 ; 3 2 | = -10
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-x²) dx = √π / 2
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