Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 06:39Z
det| 4 5 ; 4 5 | = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∫₀^∞ e^(-ψ²) dψ = √π / 2
479K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-φ²) dφ = √π / 2
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\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
∫₀^∞ e^(-t²) dt = √π / 2
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F = G m₁m₂ / r²
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
e^{i\pi} + 1 = 0
F = G m₁m₂ / r²
F = ma