Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:44Z
2ψ² + 5ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
75K
∫₀^∞ e^(-φ²) dφ = √π / 2
479K
N₂ + 3H₂ ⇌ 2NH₃
det| 7 4 ; 4 8 | = 40
276K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 3 7 ; 2 4 | = -2
390K
∇²z = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
N₂ + 3H₂ ⇌ 2NH₃