Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:45Z
∂r/∂φ = 2r
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
198K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
155K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
201K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 4 ; 1 10 | = 86
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\frac{12}{6} \sum_{i=1}^{n} i^{2}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 2 5 ; 4 3 | = -14
λ = h/p
N₂ + 3H₂ ⇌ 2NH₃