Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:34Z
E = mc²
det| 7 4 ; 4 8 | = 40
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det| 10 7 ; 4 11 | = 82
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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λ = h/p
det| 5 3 ; 7 6 | = 9
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4θ² + 9θ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-t²) dt = √π / 2
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det| 8 5 ; 5 9 | = 47
\frac{1}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O