Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:49Z
ω = 2πf
7r² + 8r + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
155K
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
366K
det| 10 9 ; 3 11 | = 83
2ψ² + 6ψ + 0 = 0
det| 5 3 ; 2 6 | = 24
263K
ω = 2πf
Fe₂O₃ + 3CO → 2Fe + 3CO₂
233K
∂ψ/∂t = 3ψ