Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:47Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12β² + 9β + 3 = 0
∂z/∂n = 8z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
191K
e^{i\pi} + 1 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
473K
2H₂ + O₂ → 2H₂O
det| 4 8 ; 3 5 | = -4
416K
4γ² + 9γ + 7 = 0
1r² + 3r + 3 = 0