Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:53Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
326K
∑_{k=1}^{n} k = n(n+1)/2
198K
7r² + 8r + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
366K
det| 9 4 ; 1 10 | = 86
201K
∑_{k=1}^{n} k = n(n+1)/2
319K