Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 22:37Z
N₂ + 3H₂ ⇌ 2NH₃
3β² + 9β + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
392K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
233K
ω = 2πf
det| 5 3 ; 7 6 | = 9
330K
12t² + 5t + 7 = 0
det| 1 4 ; 0 2 | = 2
375K
∫₀^∞ e^(-φ²) dφ = √π / 2
412K