Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:28Z
∇²α = 0
6φ² + 8φ + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
63K
∂φ/∂φ = 1φ
∫₀^∞ e^(-φ²) dφ = √π / 2
201K
det| 4 8 ; 1 5 | = 12
det| 7 4 ; 4 8 | = 40
176K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
7φ² + 2φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0
det| 12 9 ; 2 13 | = 138
\frac{8}{5} \sum_{i=1}^{n} i^{2}