Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:57Z
2ψ² + 5ψ + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
75K
N₂ + 3H₂ ⇌ 2NH₃
det| 9 4 ; 1 10 | = 86
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0
191K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
390K
∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
473K
8t² + 2t + 3 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
188K
F = ma
∫₀^∞ e^(-φ²) dφ = √π / 2