Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 00:49Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
479K
7x² + 6x + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
129K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 5 6 ; 7 6 | = -12
191K
∑_{k=1}^{n} k = n(n+1)/2
390K
5β² + 9β + 2 = 0
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
473K
∑_{k=1}^{n} k = n(n+1)/2
416K