Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:41Z
2ψ² + 5ψ + 4 = 0
∫₀^∞ e^(-t²) dt = √π / 2
75K
N₂ + 3H₂ ⇌ 2NH₃
det| 4 8 ; 3 5 | = -4
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∑_{k=1}^{n} k = n(n+1)/2
191K
∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
det| 4 4 ; 5 5 | = 0
338K
8t² + 2t + 3 = 0
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1