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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 16:46Z

7φ² + 4φ + 5 = 0

∑_{k=1}^{n} k = n(n+1)/2

326K

N₂ + 3H₂ ⇌ 2NH₃

198K

E = mc²

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

155K

d/dγ [γ^8] = 8γ^7

63K

e^{i\pi} + 1 = 0

7y² + 9y + 1 = 0

366K

∑_{k=1}^{n} k = n(n+1)/2

201K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

det| 7 4 ; 4 8 | = 40

176K

2H₂ + O₂ → 2H₂O

319K

d/dβ [β^2] = 2β^1

∑_{k=1}^{n} k = n(n+1)/2

359K

ΔS ≥ 0

263K

PV = nRT

233K

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