Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
479K
3β² + 6β + 2 = 0
det| 7 6 ; 1 8 | = 50
276K
F = ma
det| 3 6 ; 0 4 | = 12
191K
det| 3 3 ; 4 4 | = 0
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
1x² + 5x + 7 = 0
∇²ψ = 0