Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:38Z
∑_{k=1}^{n} k = n(n+1)/2
det| 11 5 ; 0 12 | = 132
75K
8β² + 2β + 0 = 0
det| 10 7 ; 3 11 | = 89
276K
∑_{k=1}^{n} k = n(n+1)/2
129K
∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1