Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:53Z
ω = 2πf
7r² + 8r + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 10 9 ; 3 11 | = 83
det| 4 6 ; 4 5 | = -4
176K
det| 5 9 ; 7 6 | = -33
319K
2ψ² + 6ψ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
359K
ω = 2πf
∂ψ/∂t = 3ψ