Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:25Z
∇ × E = −∂B/∂t
det| 10 9 ; 0 11 | = 110
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\frac{8}{9} \sum_{i=1}^{n} i^{2}
det| 4 6 ; 4 5 | = -4
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det| 3 1 ; 7 4 | = 5
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F = ma
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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∑_{k=1}^{n} k = n(n+1)/2
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10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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