Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:41Z
∂r/∂φ = 2r
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 7 4 ; 4 8 | = 40
319K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 3 7 ; 2 4 | = -2
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det| 5 6 ; 2 6 | = 18
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λ = h/p
\frac{2}{2} \sum_{i=1}^{n} i^{2}
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